If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0=x^2+9x-121
We move all terms to the left:
0-(x^2+9x-121)=0
We add all the numbers together, and all the variables
-(x^2+9x-121)=0
We get rid of parentheses
-x^2-9x+121=0
We add all the numbers together, and all the variables
-1x^2-9x+121=0
a = -1; b = -9; c = +121;
Δ = b2-4ac
Δ = -92-4·(-1)·121
Δ = 565
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{565}}{2*-1}=\frac{9-\sqrt{565}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{565}}{2*-1}=\frac{9+\sqrt{565}}{-2} $
| -7/x+10=7 | | 20/0.5=x | | 21(b-45)-51(b-56)=20b+97b | | (3x+5)^2-6(3x+5)+9=0 | | 9(q+1)=90 | | 2-4(x+2)=16+2(4+3x) | | 5^(2x)=11 | | 4^3x-2=(1/8)^2x-1 | | -7(p-91)=0 | | -4(d-7)=524 | | 81=4d+9 | | 23-3j=11 | | 100/10-x=17 | | 10(-13-x)+11=-14-63 | | x^2=3^49 | | 6v^2-19v=0 | | 4(x+1)-4=3x+5 | | 4/10-x=19 | | p(4)=1/6 | | 16=x/12+8 | | (x-8)/8=8(8x-64) | | 24x=5(x^2-1) | | -2x+50=50x+-2 | | 16^2=15^2-x^2 | | 50x+50=50x+-2 | | 20x^2+5=29x | | -2x+50=-50+-2 | | (x-4)/4=4(4x-16) | | p²-6p-24=0 | | -(7x+3)=2x^2 | | p²-6-24=0 | | (x-3)/3=3(3x-9) |